Question

Please Help! So Confused! Medal and fan will be given!

Question Below VVV

Answer 1

A basketball player makes 80% of her free throws. Recently during a very close game, she shot 5 free throws near the end of the game and missed 3 of them. The fans booed. What is the probability of her missing 3 (or more) free throws out of 5? Set up and conduct a simulation (using the random digits below) with 10 repetitions.

83234602784360127630126087268768056651093246461081275417450
17491243217468017649817480716408712807408783402746237416207
48648148631085738560871267162622568746587387234879847296948
179846198459812659816512460043380430440

Answer 2

P(3 or more missed) = p(making 0 or 1)

Pick a starting point, somehow.

Answer 3

Did you pick a starting point?

Answer 4

@tkhunny Actually I was just about to say... I know nothing about this problem. Could you please give me a better explanation? I have never done this problem before.

Answer 5

Pick a starting point. You have a list of numbers. You must start somewhere. Where shall you do that?

Answer 6

Oh okay.. so I can just pick any random number from the list? If so... I pick the first one. 8. @tkhunny

Answer 7

@mathmate please help!

Answer 8

What @tkhunny was trying to help you do is to start the simulation experiment.
Each digit represents a throw.
You have to decide which digits stand for success (8 out of 10) and which ones stand for her misses (2 out of 10).
So from (any) 5 numbers you pick, you will compile the results (2 in 3 out, etc.). This is called one trial.
Repeat the trial 10 times, and report how many out of your 10 trials that she missed 3 out of 5. Then calculate the (experimental) probability that she misses 3 out of 5.

Answer 9

So would this be okay? When I get the numbers that are from 0 - 7 it is a hit and if I get a 8 or a 9 it is a miss?

Answer 10

or no 1 -7 is a hit and 0, 8 , 9 is a miss?

Answer 11

@mathmate

Answer 12

The first one is ok, with 80% hit and 20% miss.
The second would have 30% miss.

Answer 13

So is this right:

83234
mhhhh
-----
60278
hmhhm
-----
43601
hhhmh
-----
27630
hhhhm
-----
12608
hhhmm
-----
72687
hhhmh
-----
68056
hmmhh
-----
65109
hhhmh
-----
32464
hhhhh
-----
61081
hhmmh

Answer 14

So according to your results, what is the probability that she misses 3 out of 5?

Answer 15

So in all of the repitions there is no instance where there were 3 or more hits out of 5... so is the answer: The probability of her missing 3 (or more) free throws out of 5 is 0% ... is that right? @mathmate

Answer 16

Yes, except that I would like you to specify that it is an "experimental probability" with 10 trials using random numbers starting from which series and where.

Answer 17

Wait so am I supposed to use random numbers and not go in order? @Michele_Laino

Answer 18

@Mehek14 Can does math mate mean that I have to not use the numbers in order?

Answer 19

It's perfectly ok to use the random numbers in order. IF you don't, you have to specify a systematic way to show that you did not "choose" the numbers.

Answer 20

Thank you so much! @mathmate

Answer 21

You're welcome! :)