HELP!!!! Can someone please help me with this??
Line L is perpendicular to a line m with equation -6x + 2y = -48. Line L intersects line m at (7, -3). The equation of line L, in standard form is, ________???
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OpenStudy (anonymous):
you gotta find the slope of \(-6x+2y=-48\) first before you can find the slope of the perpendicular line
do you know it?
OpenStudy (anonymous):
Yes, I know that part
OpenStudy (anonymous):
what did you get?
OpenStudy (anonymous):
for the slope i mean
OpenStudy (anonymous):
1/3x -y = -.75 I'm not sure if it's right
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OpenStudy (anonymous):
For standard form
OpenStudy (anonymous):
no it is not right
OpenStudy (anonymous):
oops no it isn't
OpenStudy (anonymous):
the slope of \(-6x+2y=-48\) is \(3\)
OpenStudy (anonymous):
Ok, I got that part, but I need the line perpendicular to that
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OpenStudy (anonymous):
your line, being perpendicular, will have a slope of \(-\frac{1}{3}\) the "negative reciprocal"
OpenStudy (anonymous):
and you have to write it in "standard form" correct?
OpenStudy (anonymous):
What is the equation of the perpendicular line in Y-intercept form? Yes, in standard form
OpenStudy (anonymous):
start with the point slope form \[y=y_1=m(x-x_1)\] using \(x_1=7,y_1=-3,m=-\frac{1}{3}\)
OpenStudy (anonymous):
I already have the slope
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OpenStudy (anonymous):
yeah and the point too
OpenStudy (anonymous):
What do you mean by the point?
OpenStudy (anonymous):
Line L intersects line m at (7, -3)
OpenStudy (anonymous):
so the point is \((7,-3)\)
OpenStudy (anonymous):
ok, I got that
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OpenStudy (anonymous):
you want to start with \[y+3=-\frac{1}{3}(x-7)\]
OpenStudy (anonymous):
How do you get from there to the standard form?
OpenStudy (anonymous):
i would multiply everything by 3 to get rid of obnoxious fraction
OpenStudy (anonymous):
let me know what you get
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
I don't know how to do that.
OpenStudy (anonymous):
\[3(y+3)=3\times -\frac{1}{3}(x-7)\]
OpenStudy (anonymous):
then the fraction is gone, you get \[3y+9=-(x-7)\] now distribute the minus sign on the right
OpenStudy (anonymous):
you good from there?
OpenStudy (anonymous):
No, we have not learned this way
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OpenStudy (anonymous):
not sure what you learned, but this is what you need if you are to put in in standard form
OpenStudy (anonymous):
Ok 3y+9=-x+7
OpenStudy (anonymous):
We have weekly quizzes, but are not taught in class for them
OpenStudy (anonymous):
ok then to put the x on the left, add x to both sides \[x+3y+9=7\] and finally subtract 9
OpenStudy (anonymous):
I don't know how to do that
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OpenStudy (anonymous):
Wait
OpenStudy (anonymous):
x+3y=-2
OpenStudy (anonymous):
Is that right?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
btw i don't believe you do not know how to subtract 9
just saying ..
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OpenStudy (anonymous):
I am exhausted right now, sorry
OpenStudy (anonymous):
So, what do I do from there? Is that the final answer?