Question

Find the derivative dy/dx for y=(x^3-5x)/(x^2-1)

Answer 1

i got a

Answer 2

yes. that is how it works

Answer 3

ok thank you :)

Answer 4

but wait. there is something wrong.

Answer 5

Those are the options ?

Answer 6

If so, then row #1 is correct!

Answer 7

yeah

Answer 8

\[y=\frac{x^3-5x}{x^2-1} \]
\[\frac{dy}{dx}=\frac{(x^2-1)(3x^2-5) - (x^3 -5x)(2x)}{(x^2-1)^2} \]
\[\frac{dy}{dx}=\frac{(3x^4-5x^2 -3x^2 +5)- (2x^4 - 10x^2)}{(x^2-1)^2} \]

Answer 9

so the first one is the answer

Answer 10

thank you!