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solve e^2x-1 = 3 for x
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Is this \[\large e^{2x - 1} = 3\] or \[\large e^{2x} - 1 = 3\]
e^(2x-1) = 3
Alright \[\large e^{2x - 1} = 3\] Remember the rules for logarithms...\(\large ln(e^{ax}) = ax \times ln(e)\) So if we apply this here, and take the log of both sides...we have \[\large ln(e^{2x - 1}) = ln(3)\] which then turns into \[\large (2x - 1)ln(e) = ln(3)\] Still with me?
I am
Great...what is \(\large ln(e) = ?\)
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1?
Right! So we really just have \[\large (2x - 1) = ln(3)\] Now just solve that for 'x'
Ln3 +1 / 2
Right! *just to make sure you mean all over 2 though...
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