Describe the vector as an ordered pair. Round the coordinates to the nearest tenth.
|dw:1447134107663:dw|
Well, hint* we know vectors are represented in terms of r and theta \[\large x = rcos(\theta)\] \[\large y = rsin(\theta)\] So if we wanted to turn this into an ordered pair \(\large (x,y)\) we would have \[\large (rcos(\theta)), rsin(\theta))\] Just plug in your 'r' and your angle and evaluate
Well, hint* we know vectors are represented in terms of r and theta \[\large x = rcos(\theta)\] \[\large y = rsin(\theta)\] So if we wanted to turn this into an ordered pair \(\large (x,y)\) we would have \[\large (rcos(\theta)), rsin(\theta))\] Just plug in your 'r' and your angle and evaluate
Let me know if that makes sense or not :)
does not make sense
i plug in what in where??
Okay...so lets think about it another way!
lol ive never heard of it being called r and theta
@bibby
No problem! That's the thing is it's impossible to know how advanced of a description I can give :D But, this will hopefully make it clear! If I take your drawing... |dw:1447134623292:dw| And make it a right triangle... |dw:1447134728199:dw| We have a right triangle...with an angle known and the hypotenuse known right?
yes i understand so i use sin(69)=x/54 to find the x value and cos(69)=x/54 to find the y value
wow i feel dumb for that seeing this in the first place thanks!!!!!
Hmm...your labeling is a little off |dw:1447134973458:dw|
well yeah thats what i meant lol
Lol okay good :P
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