help please !!! find the equation for the circle that satisfies the conditions 5) center at the origin passes through (4,7)
do you know the distance formula?
no
distance between origin (0,0) and (x,y)=(4,7) \[\sqrt{x^{2}+y ^{2}}\]
do u find radius = distance between origin and the point
is midpoint formula needed here
@marcelie do you need a help?
yes
|dw:1447143409478:dw|
okay. then
now first find radius. radius^2 = (4-0)^2 + (7-0)^2= 16+49 = 65 \[radius = 65^{1/2}\]
now you have to know , there is a theorem to find formula of a circle with radius
it is x^2 + y^2 = radius^2
so the answer is x^2 + y^2 = 65
is midpoint formula needed ?
no. you don't need to find midpoint for that. you need to know radius. that's it. wait , I will send you references
http://www.regentsprep.org/regents/math/algtrig/atc1/circlelesson.htm here it is
look at the diagram at left side on that page.
hope that helps. bye
wait..
how come on number five here they used midpt o.o
it is difference. nothing has to do with this problem
ah ok
look closely, on number 5, they don't say center is (0,0)
(0,0) is on the curve line of circle
but in our problem, (0,0) is the center. get it?
bye
the problem u asked is different from the example one
@lochana ur solution is right
yes. he confused center and origin. that's why he had that problem i guess
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