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OpenStudy (anonymous):
to what temperature does a 250.0-mL cylinder contain 0.1000 he need to be cooled in order for the pressure to be 253.25 kPa
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OpenStudy (cuanchi):
PV = nRT T= PV / nR P= 253.25 kPa (convert this to atm) V= 250.0 mL (convert this to L) n = 0.1000 moles He R = 0.082 atm L /mol K the temperature will be in Kelvins
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