Question

Solve. 14x^2 + 42x + 70 = 0

Answer 1

there are no real solutions because we have the square root of a negative number

Answer 2

are you familiar with complex numbers?

Answer 3

@judge2020 @welshfella the answer choices are
\[1\pm i \sqrt{11}\]
\[\frac{ -3 \pm i \sqrt29 }{ 2 }\]
\[\frac{ -3 \pm 2i \sqrt29 }{ 2 }\]
\[\frac{ -3 \pm i \sqrt 11 }{ 2 }\]

Answer 4

the calculation can be made easier by dividing the equation by 14
this gives
x^2 +3x + 5 = 0

Answer 5

x = [-3 +/1 sqrt(3^2 - 20)] / 2
= [-3 +/- sqrt(-11)] / 2

Answer 6

can you see which one it is?

Answer 7

recall that sqrt(-1) is written as i

Answer 8

so it's the last one? thank you!

Answer 9

yes

Answer 10

yw