Question

math fun fun

Answer 1

Break down each of those numbers into their prime factorization , for each of the roots

Answer 2

can you help me

Answer 3

243‾√

Answer 4

i get that

Answer 5

\[\sqrt{18}={\sqrt{3*3*2}}\]
for the first one

Answer 6

If an even number, i would start by pulling out as many 2's as possible, for that 18, you get 2*9, then 9 is 3*3

Answer 7

18

Answer 8

so 18 = 3^2*2

\[\sqrt{18}=\sqrt{3^2*2}=\sqrt{3^2}*\sqrt{2} = 3\sqrt{2}\]

Answer 9

you see how that works?

Answer 10

BUT HOW CAN I PUG THAT TOT HIS

Answer 11

You have to do that for all three of those roots, the only way you can combine them after that is if they are the same things under the roots

Answer 12

=(

Answer 13

12 = 6 * 2 = 3 * 2 * 2 = 3 * 2^2

8 = 2 * 4 = 2 * 2 * 2 = 2 * 2^2

so you have this

\[\large \sqrt{2*3^2}+\sqrt{3 * 2^2} + \sqrt{2*2^2}\]

Answer 14

recall that the square root of a product is the product of two square roots ...
\[\sqrt{a*b} = \sqrt{a}*\sqrt{b}\]

Answer 15

18
12
8

Answer 16

and the square root is the same as rasing to the (1/2) power

\[\sqrt{x}=x^{1/2}\]

Answer 17

-(((((((

Answer 18

look at my private message

Answer 19

so x^2 to the 1/2 power becomes x^(2/2) = x

Answer 20

those are the things you have to remember...

so you get

\[\large \sqrt{2*3^2}+\sqrt{3 * 2^2} + \sqrt{2*2^2} = 3\sqrt{2}+2\sqrt{3}+2\sqrt{2}\]

Answer 21

you can combine the terms with the same things under their roots...

Answer 22

so 5 root 2 plus 2 root 3

Answer 23

\[(3+2)\sqrt{2}+2\sqrt{3}\]

thats it... you just have to know the root properties and how to break each number into smaller factors

Answer 24

after a few practice probs, this prob will take you 30 seconds maybe

Answer 25

\[2\sqrt{3}+5\sqrt{2}\]

Answer 26

that the final answer?

Answer 27

yes, simplest form, hope you see how it breaks down

Answer 28

thanks you new post