Finding where this equals zero o.0
[(x^2+1)(3)-(3x-4)(2x)]/[(x^2+1)^2] = 0

Question

Finding where this equals zero o.0
[(x^2+1)(3)-(3x-4)(2x)]/[(x^2+1)^2] = 0

babynini · Answer

So it's not defined when the numerator = 0 correct?

lochana · Answer

no. it's not defined when denominator = 0

lochana · Answer

you can find solutions by further simplifying

babynini · Answer

right, that's what I thought but I got
x= -1/3 and 3
which makes the numerator = 0
when simplifying o.0

babynini · Answer

Simplifying we get:
[-(3x+1)(x-3)]/(x^2+1)^2]

lochana · Answer

$$\frac{[(x^2+1)3 - (3x-4)2x]}{(x^2 + 1)^2}$$

yes. your solutions are correct

lochana · Answer

now simply plug each solution in the equation. you will get zero

babynini · Answer

Right, but I got that by setting the numerator = 0 which is why i'm confused xD

lochana · Answer

yes. we normally don't think about denominator when finding solutions to 0. because you can't make the equation zero with denominator.

lochana · Answer

so we usually forget denominator and focus on numerator.

lochana · Answer

so the idea is that if you make numerator zero. while thing become zero:)

lochana · Answer

whole*

lochana · Answer

bye

babynini · Answer

Ah ok. Thanks!