Question

1. Part A.) For the f(x) = 5x + 8 and g(x) = x – 3. Calculate (f o g)(x)
Part B.) f(x) = 3x + 5 and g(x) = x². Calculate (f o g)(-3)


SHOW ALL WORK

Answer 1

Part A.) `For the f(x) = 5x + 8 and g(x) = x – 3. Calculate (f o g)(x)`
fog = f composed with g of x
( fog )(x) = f(g(x))

Answer 2

What f o g(x) is really saying is to find f(g(x)). For example, if you are asked for f o g(2), you would compute g(2), which would give you a number, let's pretend it is 5. Then you would stick that 5 into f and compute f(5), which is just f(g(2))

Say f(x) = 2x and g(x) = 4x + 2. f o g(x) = f(g(x)) = f(4x + 2) = (4x + 2)

Try it now using that!

Answer 3

so substitute all x for g(x) function into f(x) equation \[\rm f(x)= 5\color{Red}{x}+8\]\[\rm g(x)=x-3\]
\[\rm ( fog)(x) \rightarrow f(g(x))\]

Answer 4

so whats the steps and answer, best answer ill give medals to

Answer 5

I totally havve a typo in my answer, it should be 2*(4x+2)

Answer 6

like jtsrumps gave u an example \[\rm
(f og )(2) \rightarrow f(g(2))\]

Answer 7

i have idea how to do this ive been absent. where are the steps and answer

Answer 8

\[\rm f(x)= 5\color{Red}{x}+8\]\[\rm g(x)=x-3\]
substitute x for g(x) equation which is x -3

Answer 9

so whats the entire thing @Nnesha

Answer 10

for A and B

Answer 11

okay... that's how we should replace x with x-3
\[\rm f(x)= 5\color{Red}{x}+8\]

\[\rm f(\color{reD}{g(x)})= 5(\color{Red}{x-3})+8\]
now distribute (x-3) by 5

Answer 12

can you paste the whole thing in one post and then i can just use it plz

Answer 13

or message me

Answer 14

no i want you to work with me

Answer 15

im willing to igve you medals

Answer 16

i don't care about medals.
i want you to learn how to solve these types of question

Answer 17

familiar with the distributive property ?
\[\rm \color{Red}{a}(b+c)=\color{Red}{a}*b+\color{ReD}{a}*c=\color{Red}{a}b+\color{ReD}{a}c\]

Answer 18

yes not functions tho

Answer 19

alright then distribute (x-3) by 5 let me know what you get
\[\rm f(\color{reD}{g(x)})= 5(\color{Red}{x-3})+8\]

Answer 20

5x-3+8?

Answer 21

multiply both terms in the parentheses by 5
just like in that example a times b +a times c

Answer 22

5x-15+8

Answer 23

5x-23

Answer 24

hmm how did you get 23
-15+8 = ?

Answer 25

oh -7

Answer 26

yes that's correct that's it !

Answer 27

so its -7 the answer

Answer 28

no

Answer 29

\(\color{blue}{\text{Originally Posted by}}\) @Typical_karen
5x-15+8
\(\color{blue}{\text{End of Quote}}\)
there supposed to be -7 instead 23

Answer 30

5x-15+8
that's what u got after distributing by 5 right that's correct
and then combine like terms
that's it done!

Answer 31

so hoow would i put it all together

Answer 32

@Nnesha

Answer 33

what do you mean ??
you can't add combine 5x with - 7 they aren't like terms

Answer 34

i mean how do i put everything together to get my answer, so i can put it on paper

Answer 35

\(\color{blue}{\text{Originally Posted by}}\) @Nnesha
\[\rm f(x)= 5\color{Red}{x}+8\]\[\rm g(x)=x-3\]
substitute x for g(x) equation which is x -3
\(\color{blue}{\text{End of Quote}}\)
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha
\[\rm f(\color{reD}{g(x)})= 5(\color{Red}{x-3})+8\]
apply distributive property

\(\color{blue}{\text{End of Quote}}\)
\(\color{blue}{\text{Originally Posted by}}\) @Typical_karen
5x-15+8
\(\color{blue}{\text{End of Quote}}\)
and then last step combine like terms

Answer 36

make sense ?

Answer 37

yeah i guess

Answer 38

Your answer at the ens, is 5x-7 the X doesn't go away.

Answer 39

alright can you start working on part B ???
that's the same question :=))
and feel free to ask any question about that

Answer 40

Wow, good work Nnesha!

Answer 41

Thanks!! :=))