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Mathematics 20 Online
OpenStudy (anonymous):

Algebra 2 :)

OpenStudy (anonymous):

What function accurately represents the sine curve for red light?

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

what is the period of this trig function?

OpenStudy (anonymous):

um idk:(

OpenStudy (anonymous):

Is it pi/320?

jimthompson5910 (jim_thompson5910):

the period is T = 640 since the curve repeats itself every 640 nm use the formula T = 2pi/B T = 2pi/B 640 = 2pi/B B = ???

OpenStudy (anonymous):

640/ 2=320

OpenStudy (anonymous):

is the answer D?

jimthompson5910 (jim_thompson5910):

yes you should end up with B = pi/320

jimthompson5910 (jim_thompson5910):

so that's why the function is \[\Large f(x) = \sin\left(\frac{\pi}{320}x\right)\]

OpenStudy (anonymous):

That makes sense! Thank you:)

OpenStudy (anonymous):

The temperature of a chemical reaction ranges between 40 degrees Celsius and 180 degrees Celsius. The temperature is at its lowest point when t = 0, and the reaction completes 1 cycle during a 12-hour period. What is a cosine function that models this reaction? f(t) = 70 cos 12t + 110 f(t) = 110 cos 12t + 70 f(t) = −70 cos pi over 6t + 110 f(t) = −110 cos pi over 6t + 70

OpenStudy (anonymous):

I got C?

jimthompson5910 (jim_thompson5910):

which is correct.

OpenStudy (anonymous):

Yes! Thanks again :)

OpenStudy (anonymous):

Caroline has a rock stuck in her Jeep's tire. If the tire has a 48-inch diameter, how far does the rock travel in 94° of rotation? 188 pi over 15 47 pi over 90 24π 47π

OpenStudy (anonymous):

Um I got A?

jimthompson5910 (jim_thompson5910):

hopefully you used s = (x/360)*2*pi*r s = arc length x = angle in degrees r = radius I'm getting 188pi/15 = 39.374627924992 as well

OpenStudy (anonymous):

Yup:) O course!

OpenStudy (anonymous):

What are the amplitude, period, phase shift, and midline of f(x) = 7 cos(2x + π) − 3? What are the amplitude, period, phase shift, and midline of f(x) = 7 cos(2x + π) − 3? Amplitude = −3; period: π; phase shift: x = negative pi over 2; midline: y = 3 Amplitude: 7; period: π; phase shift: x = negative pi over 2; midline: y = −3 Amplitude: 7; period: 2π; phase shift: x = pi over 2; midline: y = 3 Amplitude: −3; period: 2π; phase shift: x = pi over 2; midline: y = −3

OpenStudy (anonymous):

B?

jimthompson5910 (jim_thompson5910):

correct again, you're on a roll

OpenStudy (anonymous):

hahaaha!! Thanks <3 for all you're help!

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