What are the period and phase shift for f(x) = 5 tan(2x − π)?
@ganeshie8
is the period pi?
@mathmate
y=Atan(Bx + C) + D a= amplitude for tan and cot period would be \[\rm P=\frac{ \pi}{\left| b \right|}\] phase shift c/b
p=pi/2?
hmm no for sin and cos period would be 2pi/b for tan its pi/b
yes that's correct
ok so the period would be pi/2 right
yes
pi/2=phase shift?
hmm C is what ?
What are the period and phase shift for f(x) = 5 tan(2x − π)? Period: π; phase shift: x = pi over two Period: π; phase shift: x = negative pi over two Period: pi over two; phase shift: x = negative pi over two Period: pi over two; phase shift: x = pi over two
okay so what is C in that equation ?
\[\rm y=Atan(Bx + C) + D\] f(x) = 5 tan(2x − π)?
-pi/2 as the phase shift?
correct c is negative it's c= - pi
Thanks:)
I have one last question.
Use the graph below to answer the question that follows: cosine graph with points at 0, negative 1 and pi over 2, 3 and pi, negative 1 What are the amplitude, period, and midline of the function? Amplitude: 8; period: π; midline: y = 1 Amplitude: 8; period: 2π; midline: y = 5 Amplitude: 4; period: 2π; midline: y = 5 Amplitude: 2; period: π; midline: y = 1
\[\rm y=\color{green}{A}tan(\color{blue}{B}x + \color{Red}{C}) + \color{orange}{ D}\] \[\rm f(x) = \color{green}{5} \tan(\color{blue}{2}x \color{Red}{− π})+\color{orange}{0} \]
ok. is the answer to the 2d question b?
where is the graph ? and tbh i'm not good at graphing these functions ..
i cant copy it on here:O Just use desmos.com abd type it the points:)
take a scrreenshot like i mean how would i know what is -1 x or y ??
@mathmate
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