I will fan!! I need help with some calculus questions.
To find y' you have to derive the function with respect to x \[x = \sin(x+y)\] \[1 = \cos(x+y) . (1 + y')\] \[\frac{ 1 }{ \cos(x+y)} = 1 + y'\] \[\frac{ 1 }{ \cos(x+y)} - 1 = y'\] \[y' = \frac{ 1 - \cos(x+y) }{ \cos(x+y) }\]
Thank you. I got that right. Could you check this one?
@TrojanPoem
The first, second are wrong: ddx[f(x)g(x)]=f′(x)g(x)+g′(x)f(x) The third: 0.5 (f(x))^-0.5 * f'(x) = f'(x) / 2sqrt(fx) Maybe you noticed something, I didn't. why do you think the third is wrong ?
I knew it was either the third or none of them. The third one is confusing to me.
The second derivative of absolute is :\[\frac{ u.u' }{ |u| }\] In the third: \[\frac{ d }{ dx } \sqrt{f(x)} = \frac{ d }{ dx } f(x)^{0.5} = 0.5 . f(x)^{0.5 - 1} * f'(x)\] \[0.5. f(x)^{-0.5} * f'(x) = \frac{ f'(x) }{ 2 \sqrt(fx) }\]
Okay, so the third one is the true statement.
I believe so.
Thank you. it was correct! (:
Any time.
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