Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function. f(x) = -2x4 + 4x3 + 3x2 + 18
+18 * -2 = -36 so you need to list the factors of -36
eg +/- 1 , +/- 2 , etc
±6,±6 ±2,±18 ±3,±12 ±4,±9
Right?
@welshfella
hmm
?
hmm ho would that work ? are we going to divide all factors by 2 maybe
how**
p/q method \[\rm \frac{ p }{ q }=\frac{ \pm~ list~factors~of~ constant~term }{\pm~ list ~factors~of~leading ~coefficient }\]
ah yes - i'd forgotten that formula. So +/- 18 would not be included
So I divide all those numbers by 2?
- to be honest I'm not sure ....
no i was asking should we divide by 2..
It's been a long time since i did these
p/q method \[\rm \frac{ p }{ q }=\frac{ \pm~ list~factors~of~ constant~term }{\pm~ list ~factors~of~leading ~coefficient }\] do this divide factors of constant term by factors leading coefficient
i suppose 18 would be included as its 18 / 1
???
what do you mean welshfell ? sorry i don't get it .. :o
well 18 is a factor of the constant term and 1 is a factor of -2
Yes, you would include 18 for precisely the reason you just described.
I guess I should revise this stuff!!!
f(x) = -2x4 + 4x3 + 3x2 + 18 leading coefficient = -2 so factors are \[\pm 1 , \pm2 \] constant term is 18= so factors 1 ,2 ,3 , 6,9,18 so we should include all of them
yea
\[\rm \frac{p}{q}= \frac{ \pm 1 , \pm 2 , \pm 3,\pm 6, \pm 9,\pm 18}{\pm 1 , \pm2}\] now just divide and remember each number at the numerator are dividing by1 and 2
ofc +/- 1 , +/- 2
yes thats it
±1, 2, 3, 6, 9, 18, 1/2, 3/2, 9/2
Of course its possible that none of those are roots but that'f not relevant to the question.
^^ye that to find real you can use synthetic division or just replace all x's with each possible solution if you get zero as final answer then that would be the real zero
Just out of interest I'll do this one on my calc...
So what I posted should be the answer that's needed for this question?
yes
ye use calculator for real zeros ;P
Thank you two
real zeros are 2.89 and -1.524 the other 2 roots are complex
yw
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