Question

Express the complex number in trigonometric form.

-6 + 6square root of 3i

Answer 1

\[-6+6\sqrt{3i}\]

Answer 2

??

Answer 3

Yes but the i isn't under the square root

Answer 4

or
\[-6+6\sqrt{3}i\]

Answer 5

ok
\[-6+6\sqrt{3}i=-12(\frac{ 1 }{ 2 }-\frac{ \sqrt{3} }{ 2 }i)\]

Answer 6

x = -6
y = 6sqrt(3)

tan theta = 6sqrt(3) / 6

theta = 60 ( in 2nd quarter ) = 120 = 2pi/3

|Z| = sqrt( (-6)^2 + (6sqrt(3))^) = 12

Z = |Z| ( CosTheta + sintheta)
= 12 (cos2pi/3 + sin2pi/3)

Answer 7

\[=12(\frac{ -1 }{ 2 }+i \sqrt{3}/2)\]

Answer 8

Thank you @TrojanPoem and @jango_IN_DTOWN!! :)