Question

help please on this last question

Answer 1

What's the question?

Answer 2

Look at the picture of a scaffold used to support construction workers. The height of the scaffold can be changed by adjusting two slanting rods, one of which, labeled PR, is shown:

.

Part A: What is the approximate length of rod PR? Round your answer to the nearest hundredth. Explain how you found your answer stating the theorem you used. Show all your work.

Part B: The length of rod PR is adjusted to 18 feet. If width PQ remains the same, what is the approximate new height QR of the scaffold? Round your answer to the nearest hundredth. Show all your work.

Answer 3

Can you attach the picture?

Answer 4

file:///Users/Ink/Desktop/5463c1a1e4b05b0e1f1937f9-kitkat1-1415823787803-03_09_part2_g3_q3.jpg

Answer 5

@livias.random

Answer 6

Sorry that link doesn't work. If you click the blue 'attach file' button you should be able to link?

Answer 7

@livias.random

Answer 8

Okay, so you have two lengths of a right angled triangle. Do you know what equation / theorem you should use?

Answer 9

i forgot it

Answer 10

You want Pythagoras' Theorem.
\[c ^{2}=a ^{2} +b ^{2}\]
where c is the diagonal, and a and b are the other 2 sides.

Substitute your values for a and b into the equation

Answer 11

\[c ^{2} =14^{2} + 9^{2}\]

Answer 12

i think thats wrong @livias.random

Answer 13

Why?

Answer 14

nevermind i thought i put the values in the wrong place @livias.random

Answer 15

no problem. Anyway, now you have to simplify.

\[c ^{2}=14^{2}+9^{2}\]
\[c = \sqrt{14^{2}+9^{2}}\]

That's a sum that you should just be able to do on a calculator

Answer 16

16.64331698 @livias.random

Answer 17

Exactly. I think the question said to round to the nearest hundredth? So 16.643 ft

Answer 18

you mean 16.64 @livias.random u rounded to the nearest thousandth

Answer 19

Oh yeah sorry!

Answer 20

ok now what do i do?

Answer 21

@imqwerty

Answer 22

@Vocaloid

Answer 23

Well that's the answer for a. Do you have any idea how to start b?

Answer 24

no I'm just getting into this subject

Answer 25

okay well you're altering the diagonal (c) but keeping (a) the same.
Try putting those values of (a) and (c) into the equation I showed you earlier

Answer 26

IM A littLe confused @livias.random

Answer 27

@mjmahmood

Answer 28

nevermind i got it