An acrobatic airplane performs a loop at an airshow. The centripetal acceleration the plane experiences is 14.7 m/s2. If it takes the pilot 45.0 seconds to complete the loop, what is the radius of the loop? Round your answer to the nearest whole number.

Question

An acrobatic airplane performs a loop at an airshow. The centripetal acceleration the plane experiences is 14.7 m/s2.  If it takes the pilot 45.0 seconds to complete the loop, what is the radius of the loop? Round your answer to the nearest whole number.

anonymous · Answer

$$\huge a_c=\frac{ 4\pi^2r }{ T^2 }$$
$a_c$ is the centripetal acceleration
T is the time it takes to complete 1 revolution (AKA the period)
r is the radius

shamim · Answer

U can also say
a=omega^2*r

shamim · Answer

Omega=2*pi/T

irishboy123 · Answer

some more flesh

$\huge a_c= \omega^2 \,r =\left( \frac{ 2\pi }{ T }\right)^2 r = \frac{ 4\pi^2 }{ T^2 }r$