Mathematics
8 Online
OpenStudy (abbycross167):
does this graph show a direct variation?
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OpenStudy (abbycross167):
|dw:1447297786275:dw|
jimthompson5910 (jim_thompson5910):
As long as it
a) goes through the origin (0,0)
AND
b) is a straight line
then it's a direct variation graph
jimthompson5910 (jim_thompson5910):
all direct variation equations are in the form `y = k*x` (k is some fixed number)
`y = 2x` is in the form `y = k*x` where in this case `k = 2`
OpenStudy (abbycross167):
Oh ok @jim_thompson5910 would you mind checking a few more equation s to
OpenStudy (abbycross167):
*equations to see is f they are diDirect Variation
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jimthompson5910 (jim_thompson5910):
sure
OpenStudy (abbycross167):
ok thank you!
OpenStudy (abbycross167):
y = (3/4)x
I'm pretty sure this is one
OpenStudy (abbycross167):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
yes k = 3/4 in this case. Hopefully you can see how
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OpenStudy (abbycross167):
Ok thats what I thought it was
OpenStudy (abbycross167):
y = -1
This one isn't right?
jimthompson5910 (jim_thompson5910):
nope because it's not in the form y = k*x
OpenStudy (abbycross167):
y = (5/2)x
And this one is?
jimthompson5910 (jim_thompson5910):
what is k equal to here?
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OpenStudy (abbycross167):
5/2
jimthompson5910 (jim_thompson5910):
yep, you got the hang of this
OpenStudy (abbycross167):
ok Thank you!!! you really helped me!!
jimthompson5910 (jim_thompson5910):
you're welcome