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Mathematics 8 Online
OpenStudy (abbycross167):

does this graph show a direct variation?

OpenStudy (abbycross167):

|dw:1447297786275:dw|

jimthompson5910 (jim_thompson5910):

As long as it a) goes through the origin (0,0) AND b) is a straight line then it's a direct variation graph

jimthompson5910 (jim_thompson5910):

all direct variation equations are in the form `y = k*x` (k is some fixed number) `y = 2x` is in the form `y = k*x` where in this case `k = 2`

OpenStudy (abbycross167):

Oh ok @jim_thompson5910 would you mind checking a few more equation s to

OpenStudy (abbycross167):

*equations to see is f they are diDirect Variation

jimthompson5910 (jim_thompson5910):

sure

OpenStudy (abbycross167):

ok thank you!

OpenStudy (abbycross167):

y = (3/4)x I'm pretty sure this is one

OpenStudy (abbycross167):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

yes k = 3/4 in this case. Hopefully you can see how

OpenStudy (abbycross167):

Ok thats what I thought it was

OpenStudy (abbycross167):

y = -1 This one isn't right?

jimthompson5910 (jim_thompson5910):

nope because it's not in the form y = k*x

OpenStudy (abbycross167):

y = (5/2)x And this one is?

jimthompson5910 (jim_thompson5910):

what is k equal to here?

OpenStudy (abbycross167):

5/2

jimthompson5910 (jim_thompson5910):

yep, you got the hang of this

OpenStudy (abbycross167):

ok Thank you!!! you really helped me!!

jimthompson5910 (jim_thompson5910):

you're welcome

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