Question

Please help me! I am so stressed and confused with this problem!

Answer 1

\[\sin(\cos^{-1} u)\]

Answer 2

How would I simplify this?

Answer 3

try
sin(cos^-1 u) =cos(90-(cos^-1 u))

Answer 4

expand that using cos(A-B) formula

Answer 5

nvm...you'll just get back ur original expression

Answer 6

you can also make a right triangle

Answer 7

let v=arccos(u)
then cos(v)=u

then find sin(v) after drawing the right triangle thingy

Answer 8

if you don't like to draw you can just use the identity sin^2(v)+cos^2(v)=1

Answer 9

@freckles Can you please help? I still don't get it and it's really bothering me :(

Answer 10

have you tried replaced cos(v) with u yet?

Answer 11

\[\sin^2(v)+\cos^2(v)=1 \\ \sin^2(v)+u^2=1 \\ \text{ just solve for } \sin(v)\]

Answer 12

are you there?

Answer 13

\[\sin(v)>0 \text{ by the way since } \arccos(u) \in [0,\pi]\]

Answer 14

ok

Answer 15

ok you have solved for sin(v)?