For each function find f(-2), f(-0.5), and f(3) Are these correct 8. F(x)= 3/8x -3 1. F= -8 2. F= 4.6 3. F=2.3
f(x) = (3/8) * x - 3 or is that x supposed to be part of that denominator
group the thing with bra-kets for fractions , not sure how you got -8 for the first f(-2), replace x with -2, evaluate for what f(x)=
I'm sorry I don't understand ): can you show me how to do the first one and I'll do the other two
yes, did i type it in right, the x is multiplied by 3/8 right, it is not 3/(8x) is it
Correct (: it is multiplied by 3/8
f(-2) is the value of f(x) when x=-2, let x=-2, substitute -2 in for all x's f(-2) = (3/8) *(-2) - 3 = -6/8 - 3
negative six eights minus 3, then simplify more, let 3 become 24/8, to have same denominator , so we can combine fractions
-(6/8) - (24/8) = -30/8
you can reduce that to -15/4 f(-2) = -15/4
----- if x=3 like the last one to figure f(3) you get (9/8) - 3 simplify
Do I do anything with the -2?
no, -2 is just the x value, f(-2) is the y value for a point on the graph of the function
My problem is multiplying with fractions
the function f(x) takes any x value you pick along the horizontal x axis, and gives it a y value, it is a rule machine to go from a chosen x value to a corresponding y value
\[\frac{ a }{ b } * \frac{ c }{ d }=\frac{ a*c }{ b*d }\] you just multiply top and bottom seperate like that
so for 9/8 times -2, you can think of -2 as -2/1
the negative 2 multiplies into the numerator
Oh okay that makes sense (: okay one sec I'm gonna do the problems let me know if they are right (:
to be able to add the fractions, i had to make them both over the same denominator. i multiplied -3 by 8/8 ,
So I got f(-0.5)= 2.6
let's see what you did . they are mixing decimals and fractions, it is messy you can keep x as -0.5 or make it -1/2
f(-0.5) = (-1.5)/8 - 3
can you do the arithmetic with a calculator? for class
I did 3/8 multiplied by -1/2 instead of -0.5 then I got -3/16 -3 then I put a 1 under the 3 to make it -3/16 - 3/1 and I got -6/16
Is it -3/8
you were on the right traack, remember to add or subtract fractions, they have to be both over the same denominator -3/16 - 3*(16/16)
I don't understand that part ☹
you got the multiplying fractions down, multiply top and bottom together individually addition and subtraction requires the same denominator first
you can add 16ths to 16ths, but you cant add 16ths to 87ths without changing things, the bottom has to be the same
\[\frac{ a }{ c } + \frac{ b }{ c } = \frac{ (a+b) }{ c }\]
Can we start over Okay so the problem is f(x) = 3/8 (-0.5)-3 F(-0.5) = 3/8 times -0.5 Then what?
we can keep the -1/2 you used, you did that part right (-3/16) - 3 from here you have to put the whole number 3 into 16ths, need same denominator to combine fractions
Would you be fine doing this with me through snapchat so I can show you what I did
i dont have that
multiply the 3 by (16/16) 16/16 is just 1, you are only multiplying by 1, it doesnt change anything
it becomes 48/16 which is the same as 3
So -3/16 -3 times 16/16?
yep.. review "common denominators" if you forgot about that ... then you can combine fractions, -3/16 - 48/16
-51/16 or you can approximate with decimals since x is a decimal
Answer : f(-0.5)= -9
Oh nevermind you add not multiply woods
-3.18 is the answer??
-51/16, is that what the calculator says.. looks right
-3.1875
Go for the last one, ill check it at the end, nothing new just a different x value
Thank you!!!!Can you help me with the last one?
Ok so f(3) = 3/8 (3)-3 correct?
6/8 -3?
Is this the answer?? F(3) = 3.75
@DanJS
sorry missed this notification, if x is 3 \[f(3) = \frac{ 3 }{ 8 }*3 - 3 ~~~~ =~~~~\frac{ 9 }{ 8 } - \frac{ 24 }{ 8 } \]
= (9-24) /8 = -15/8
you just need to practice adding vs multiplying fractions, this time you added the numerators in the (3/8)*3
Oh okay thank you so so much!!! Your awesome (:
remember the rules, i think i typed them with the a,b,c,d, general fractions somewhere here
Would you mind helping me with a new problem?
And I will thank you(:
ok
It's fine I'm going to bed thank you for your help! (:
ok, welcome, i may be on tomorrow also if you are working
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