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Mathematics 7 Online
OpenStudy (zned6559):

what is the derivative of (sin(e))^x

OpenStudy (anonymous):

the deriv of sin(x) is cos(x) and solve as a chain rule

OpenStudy (anonymous):

the derivative of e^x is e^x

OpenStudy (zned6559):

the answer is ln(sin(e)) (sin(e))^x but how do you get to this

OpenStudy (trojanpoem):

@asong195 , The x isn't the power of e , but the whole thing.

OpenStudy (trojanpoem):

assume you have y = u^v take ln for both sides lny = vlnu (derive) y'/y = v'lnu + v * u'/u y = u^v y' = u^v v' ln u + v * u^(v-1) * u'

OpenStudy (trojanpoem):

You can use the last formula for deriving or add ln yourself.

OpenStudy (trojanpoem):

y = (sin(e))^x ln y = x lnsin(e) (notice that lnsine is a constant) y'/y= lnsin(e) (from the main y) y' = ylnsin(e) = (sin(e))^x * lnsin(e)

OpenStudy (zned6559):

how come you don't derive lnsin(e)

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