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Mathematics 13 Online
OpenStudy (anonymous):

What quadrant is 11pi/3 in? Find sin 0, cos 0, and tan 0. Find a positive and negative coterminal angle

OpenStudy (anonymous):

@zepdrix Can you help me on this one?

zepdrix (zepdrix):

Well we know the boundaries for each quadrant, right? The first quadrant ends at pi/2 the second quadrant ends at pi the third quadrant ends at 3pi/2 So let's compare our 11pi/3 to each of these values and see where it lies. Get a common denominator between pi/2 and 11pi/3. Which is larger?

zepdrix (zepdrix):

no no no let's not do that :) my bad.

OpenStudy (anonymous):

Haha okay!

zepdrix (zepdrix):

11pi/3 is a really big angle, it's been spun around the entire circle a few times. Let's first find our co-terminal angles. We'll "unwind" it. Let's subtract some 2pi's from it.

zepdrix (zepdrix):

\[\large\rm \frac{11\pi}{3}-2\pi=?\]

OpenStudy (anonymous):

9/3?

OpenStudy (anonymous):

9pi/3?

zepdrix (zepdrix):

No. Need to get a common denominator before you can perform subtraction.

OpenStudy (anonymous):

5pi/3?

zepdrix (zepdrix):

Ok great. So that's a `positive angle` which is co-terminal with 11pi/3. How do we find a `negative angle` which is also co-terminal? Any ideas? :)

OpenStudy (anonymous):

Multiply by negative 1?

OpenStudy (anonymous):

It's in the second quadrant right?

zepdrix (zepdrix):

Multiply by -1.. Hmm, no. But that was a clever idea. We'll "unwind" the angle even further. We'll subtract another 2pi from it. Q2? No.

OpenStudy (anonymous):

Okay, -pi/3

OpenStudy (anonymous):

What quadrant is it in?

zepdrix (zepdrix):

Ok good :) So that answers the third question they asked.

zepdrix (zepdrix):

-pi/3 is probably the best angle to use to figure that out. Where does -pi/3 put you?

OpenStudy (anonymous):

Third?

zepdrix (zepdrix):

Where is pi/3 located?

zepdrix (zepdrix):

You gotta remember these three at the very least, pi/6 pi/4 and pi/3 those are important :)

OpenStudy (anonymous):

Okay, im not sure where though

zepdrix (zepdrix):

|dw:1447356525562:dw|

zepdrix (zepdrix):

|dw:1447356583086:dw|So then if pi/3 puts us this far in the first quadrant

zepdrix (zepdrix):

|dw:1447356628088:dw|Then negative pi/3 is the same distance but spun in the opposite direction, ya?

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