A spaceship moving with an initial velocity of 58.0 meters/second experiences a uniform acceleration and attains a final velocity of 153 meters/second. What distance has the spaceship covered after 12.0 seconds?

Question

anonymous · Answer

7.9 or 8?$$(vf-vi) \div t=d$$

anonymous · Answer

(153 m/s - 58 m/s) / 12s = 
95m/s / 12s = 7.9

anonymous · Answer

7.9 meters

irishboy123 · Answer

use $v = u + at$ to get the acceleration


then $v^2 = u^2 + 2ax$ to get the distance travelled

anonymous · Answer

or$$v_f^2 = v_i^2 + 2a \Delta d$$