Question

A 114-turn square coil of side 20.0 cm rotates about a vertical axis at ω = 1.56 103 rev/min as indicated in the figure below. The horizontal component of Earth's magnetic field at the coil's location is equal to 2.00 10-5 T.
Calculate the maximum emf induced in the coil by this field.

Answer 1

\( \mathbf{Faraday's \; law}\)


\( \large \mathcal{E} = -N {{d\Phi} \over dt} \)


do you know how to apply that?

usually, we get for symmetrical loops \(\Phi = \mathbf{B} .\mathbf{A} \)

so \(\dot{\Phi} = \mathbf{B} .\dot{\mathbf{A}} \), if the field is constant


that's the trick here :p

you didn't include the drawing, but you can clearly introduce a sinusoid as \(A(t)\). meaning \(\dot \Phi = B \times \dot A(t)\) So, \(\color{red}{ \large \mathcal{E} = -NB {{dA} \over dt} }\(\color{blue}{\text{Originally Posted by}}\) @jpalmer
A 114-turn square coil of side 20.0 cm rotates about a vertical axis at ω = 1.56 103 rev/min as indicated in the figure below. The horizontal component of Earth's magnetic field at the coil's location is equal to 2.00 10-5 T.
Calculate the maximum emf induced in the coil by this field.
\(\color{blue}{\text{End of Quote}}\)
\)