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Mathematics 12 Online
OpenStudy (ashking1):

State the domain of the rational function. f(x) = 12/13-x

OpenStudy (anonymous):

the domain is \[x \neq 13\]

OpenStudy (ashking1):

All real numbers except 13. or All real numbers except -13 and 13.

OpenStudy (anonymous):

all real numbers except 13

OpenStudy (ashking1):

thx

OpenStudy (anonymous):

because if it is -13 then the denominator will not equal zero

OpenStudy (ashking1):

can u help with one more

OpenStudy (anonymous):

sure

OpenStudy (ashking1):

oh ok i get you

OpenStudy (ashking1):

Find the vertex of the graph of the function. f(x) = (x + 6)2 + 3

OpenStudy (ashking1):

(0, -6) ( 3, 0) ( 3, -6) ( -6, 3)

OpenStudy (anonymous):

is the equation \[(x+6)^{2}+3\] or is the equation 2(x+6)+3

OpenStudy (ashking1):

first one

OpenStudy (anonymous):

the answer is (-6,3)

OpenStudy (ashking1):

thank you so much

OpenStudy (anonymous):

because u already are given the completed the square version of the answer therefore all you need to do is look at your question. the equation for completing the square will usually look like \[(x-a)^2+b\] so therefore the vertex will be (a,b) This means that whatever is inside the bracket will usually have the opposite sign(+/-) and whatever is outside the bracket will have the same sign as the equation. So in your case the formula inside the bracket was (x+6)^2+3 That meant that the a=-6 and the b=3 thus the vertex was (-6,3)

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