Question

An airplane is flying 22 degrees north of east at a speed of 810 km/h. How fast is it moving to the north?

Answer 1

I got 750 is that right?

Answer 2

@Directrix

Answer 3

>I got 750 is that right? Where is the work for this.

I don't know Physics well at all.

Answer 4

From Phone-A-Friend @Douglas

The northern component (Vn) of the velocity is:

Vn = V{sin(Θ)}

Where V is the magnitude of the Velocity (a.k.a the speed) and Θ is the angle North of East.

Vn = 810{sin(22º)} = ?

Answer 5

@mamabama disagrees and offers this:

Difficult to explain without a triangle but here:

The north component of the planes velocity is 810sin(22) = 303.4

The east component is 810cos(22) = 751.0

So the plane is moving north at 303 km/h

Answer 6

thank you so much and im sorry but my computer froze for like half an hour -.-'

Answer 7

Don't assume that either of these is correct without checking.

Answer 8

yeah but I still believe it has to be 750 :/

Answer 9

\[\huge v_\text{North}=|v| \sin (\theta)\]
By triangular orthogonal decomposition.

Answer 10

@Directrix Both answers you posted are the same

Answer 11

not really one is 750 and the other one is 810

Answer 12

@Daniellelovee No
His first post:
`Vn = 810{sin(22º)} = ?`

His second post:
`The north component of the planes velocity is 810sin(22) = 303.4. So the plane is moving north at 303 km/h`

They are the same since 810sin(22)=303.4

Answer 13

East component of the plane velocity is=810*cos22=?

Answer 14

And north component of the plane velocity is=810*sin22=?

Answer 15

U hv to know perpendicular vector resolving