find a polynomial that satisfies the given parameters . A fifth degree polynomial with only two roots
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
lol did you pick them yet?
OpenStudy (lisa123):
2 and 3?
OpenStudy (anonymous):
ok fine
OpenStudy (anonymous):
then one factor is \((x-2)\) and another has to be \((x-3)\) right?
OpenStudy (lisa123):
yes
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ok good
now \[(x-2)(x-3)\] is only a polynomial of degree 2 we have to kick it up to degree 5 without introducing any new zeros
OpenStudy (anonymous):
any ideas? there are a couple different ways to do it
OpenStudy (lisa123):
the conjugates? or imaginary numbers
OpenStudy (anonymous):
you could find a quadratic with no real roots like say \(x^2+1\) and multiply it by that, but you would still have a problem since that would only be degree 4 not 5
OpenStudy (anonymous):
you can make on zero multiplicity 2, and one zero multiplicity 3, that would do it
do you know what that means (no is a fine answer, just asking)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lisa123):
yes that means both would be x^2
OpenStudy (anonymous):
no
the factors would be raised to the power of 2 and 3
OpenStudy (anonymous):
for example \[(x-2)^2(x-3)^3\] is a polynomial of degree 5 with two zeros