find a polynomial that satisfies the given parameters . A fifth degree polynomial with only two roots
lol did you pick them yet?
2 and 3?
ok fine
then one factor is \((x-2)\) and another has to be \((x-3)\) right?
yes
ok good now \[(x-2)(x-3)\] is only a polynomial of degree 2 we have to kick it up to degree 5 without introducing any new zeros
any ideas? there are a couple different ways to do it
the conjugates? or imaginary numbers
you could find a quadratic with no real roots like say \(x^2+1\) and multiply it by that, but you would still have a problem since that would only be degree 4 not 5
you can make on zero multiplicity 2, and one zero multiplicity 3, that would do it do you know what that means (no is a fine answer, just asking)
yes that means both would be x^2
no the factors would be raised to the power of 2 and 3
for example \[(x-2)^2(x-3)^3\] is a polynomial of degree 5 with two zeros
ohh okay. could it also be (x-2)^3(x-3)^2 ?
@satellite73
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