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Solve x2 + 2x + 9 = 0.
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@pooja195
Is this x^2 + 2x + 9 = 0?
Yes.
hope you are allowed complex solutions yes?
because the two answers will not be real numbers
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oh ok since 2 is even, easiest to complete the square
subtract 9 from both sides what do you get?
4.5
Sorry I'm a little disoriented.
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\[x^2+2x+9=0\] subract \(9\) from both sides
x^2 + 2x = -9
ok good
now what is half of 2?
1
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right and \(1^2=1\) so go right to \[(x+1)^2=-9+1\\ (x+1)^2=-8\]
that means \[x+1=\pm\sqrt8\\ z=-1\pm\sqrt{-8}\]
Is there more to do?
write \(\sqrt{-8}\) as \(\sqrt{8}i\)
subtract 1 from both sides?
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then since \(\sqrt8=2\sqrt2\) final answer is \[-1\pm2\sqrt2 i\]
Oh!
Wouldn't it be -1 +2i sqrt 2?
yeah what you said
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Alright, thanks.
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