Find the x-intercepts (if any) for the graph of the quadratic function.

6x2 + 12x + 5 = 0

Give your answers in exact form. Show your work.

Question

Find the x-intercepts (if any) for the graph of the quadratic function.

6x2 + 12x + 5 = 0

Give your answers in exact form. Show your work.

astrophysics · Answer

You can use quadratic equation $$x = \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }$$ where a = 6, b = 12, and c = 5

danjs · Answer

solve what you have for x if there are any solutions

danjs · Answer

yeah that solv's the general form for x..

danjs · Answer

ax^2+ bx+c=0

anonymous · Answer

I dont get it

anonymous · Answer

I SUCK AT MATH

astrophysics · Answer

Your equation is in the form of $$ax^2+bx+c=0$$ so we can use that formula I wrote above called the quadratic formula and just plug in the values for a, b, and c and solve for x, it will give you your x - intercepts

anonymous · Answer

6x^2+12x+5=0

anonymous · Answer

@Astrophysics

astrophysics · Answer

Yes so a = 6, b = 12, and c = 5 use $$x = \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }$$ you will get two values since it's + and -

astrophysics · Answer

You're replacing the a,b,c in that formula with the numbers 6,12,5

anonymous · Answer

I give up :(

astrophysics · Answer

That's because you didn't even try, just plug in the values into the equation nothing to it