A student is trying to solve the system of two equations given below: Equation P: y + z = 6 Equation Q: 3y + 4z = 1 Which of the following is a possible step used in eliminating the y-term?
@ LegendarySadist
a. (y + z = 6) ⋅ 4 b. (3y + 4z = 1) ⋅ 4 c. (y + z = 6) ⋅ −3 d. (3y + 4z = 1) ⋅ 3
please help will give medal
you would multiply the first equation by a -3 this will give you : -3y - 3z = -18 3y + 4z = 1 --------------- 0 + z = -17 z = -17 as you can see, when added, the y terms cancel out...they are eliminated answer is C
i don't understand how you did that?
easy
what do you mean easy?
for the first equation multiple A -3
what is a -3
1?
do you know what the elimination method is, have you ever done elimination previously?
no
watch this video and tell me what your learned
when your done tell me and im ask you a question
Well if we want to eliminate the y-term, we need to either make the y term above it equal to it and then subtract (substitution method) or make the number above it equal to it's negative and then add (addition method).
So if there is an equation like x+y=-3 and x-y=1 you add through columns to find the answer
Let's say we have the equations 2x+y=4 4x+3y=7 If we want to get the y alone, we would mutiply the entire top by 2 and then subtract. 2(2x+y=4)→4x+2y=8 With this we would subtract the bottom equation by the top. So 4x+2y=8 −(4x+3y=7) to get −y=1 In this example I was eliminating the x variable with the substitution method. Understand how the process works?
yes thank you so much!
welcme i have to go so bye
ok bye
Join our real-time social learning platform and learn together with your friends!