What is the equation of a line that passes through (-6, 2) and has a slope of -1/2?

Question

zpupster · Answer

you will need point slope form:
$$y-y1=m(x-x1)$$
we know our slope=m=-1/2 
and x1 = -6
y1 = 2 
plug those in

anonymous · Answer

y-2=-1/2(x-6)

anonymous · Answer

Is that the answer?

zpupster · Answer

not yet we should now put it in slope intercept form
$$y=mx+b$$

can you do that

anonymous · Answer

So... is it -1/2x-1

zpupster · Answer

also there was a mistake with the sign
y-2=-1/2(x-6)

should be
y-2=-1/2(x-(-6))
y-2 = -1/2(x+6)

anonymous · Answer

so its y=-1/2x+5?

zpupster · Answer

y-2 = -1/2(x+6) distribute the -1/2
y-2 = -1/2x -3 add 2 both sides
y=-1/2x-1

zpupster · Answer

here you see our point on the line

anonymous · Answer

ok

anonymous · Answer

so what would the equation be?

zpupster · Answer

well you can see it above 
or you can see it on the graph

anonymous · Answer

i have four choices


a:y=x/2-2
b:y=-x/2-1
c:y=2x+1
d:y=-2x-1