Question

What is the equation of a line that passes through (-6, 2) and has a slope of -1/2?

Answer 1

you will need point slope form:
\[y-y1=m(x-x1)\]
we know our slope=m=-1/2
and x1 = -6
y1 = 2
plug those in

Answer 2

y-2=-1/2(x-6)

Answer 3

Is that the answer?

Answer 4

not yet we should now put it in slope intercept form
\[y=mx+b\]

can you do that

Answer 5

So... is it -1/2x-1

Answer 6

also there was a mistake with the sign
y-2=-1/2(x-6)

should be
y-2=-1/2(x-(-6))
y-2 = -1/2(x+6)

Answer 7

so its y=-1/2x+5?

Answer 8

y-2 = -1/2(x+6) distribute the -1/2
y-2 = -1/2x -3 add 2 both sides
y=-1/2x-1

Answer 9

here you see our point on the line

Answer 10

ok

Answer 11

so what would the equation be?

Answer 12

well you can see it above
or you can see it on the graph

Answer 13

i have four choices


a:y=x/2-2
b:y=-x/2-1
c:y=2x+1
d:y=-2x-1