The endpoints of line AB are A(9,4) and B(5,-4). The endpoints of the image after a dilation are A(6,3) and B(3,-3). Find the scale factor and explain each of your steps
Ok, let's graph this, and see if it can help you visualize it.
The points are plotted here: https://www.desmos.com/calculator/mclsqhwnkc
What do you notice?
the first one is longer than the dialation one
Well, yeah. The red points are the endpoints of the translated segment.
I mean, how do you think we could find the scale of dilation?
yes i got that
The scale of dilation is, for example, take: (x*3,y*3) The dilation is a scale of 3 (x*?,y*?) How do you think we can find the scale of dilation for this problem?
i dont know how to find the scale factor but i know it is less than 1
You're already on the right track.
I'm going to edit the coordinates on desmos a bit to help you visualize it.
ok
Ok, look on desmos
this is what i got graphing the coordinates
Look at the bottom
There are little sliders
Where it says n1 = 1 and n2 =1
If you play around with those, you can see the dilations visually.
Try and find A(6,3) and B(3,-3)
im confused what are we looking at
Do you see the little sliders that say n1 = 1 and n2 =1
On desmos
no
See it in the lower left corner?
I built a little dilation playground for you to help you understand :P if you play around with those sliders, you can see the dilations real time
i dont have those on my screen
Oh, sorry there's a new link: https://www.desmos.com/calculator/qjmzzqfz46
Try now.
Click and drag the sliders to see the dilations.
ok i got them now so what am i doing with them
If you move the sliders around, you can visualize the dilations.
So, using these points do you think we can create A(6,3) and B(3,-3)?
im getting the red coordinates not the green
wait nevermind
Look, you have to move the sliders:
i got that but this is very confusing i cant get the sliders to the right coordinates
That's right.
We can't
Why?
ok ?
(By the way, sorry I'm dragging this out. I just want you to understand this thoroughly.)
(and I also want it to be fun :P)
Anyway, clearly we can't just multiply x and y by certain numbers to dilate certain figures.
Here's why.
When you multiply x and y by different variables, you assume that (0,0) (the origin) is the center of dilation.
If you can't multiply these variables, though, the only answer is, the origin is not our center point for dilation...
Which means, to figure out our scale of dilation, we can't just find these numbers, we're going to have to use ratios.
that makes no sense and i have to write down all my steps to find my scale factor and i cant do that doing it this way
Don't worry, you'll be able to.
All we have to do is find the center of the dilation, then we can find the scale easily.
Let me show you.
I'm sorry if this is confusing you :(
i just have no idea and i have alot going on in my head so its hard to focus on this but i have to do it
I'm so sorry. Look here: https://www.desmos.com/calculator/lttgxf6exs This is how I found the center of dilation. I just drew lines that went from the first A to the second A, and from the first B to the second B, and where they intersect must be the center of dilation.
So, the center is (-3,0)
Now, to find the scale.
ok
I haven't done this in a while, but I think it's just the slopes of the line...
i dont understand why we need those lines what are they what do they do to find the scale factor
So, I think it's (A*1/3) and (B*-1/2)
Let's check.
but what are the steps to get to that
Ugh... I'm so sorry stuck... I'm kinda lost. I'm trying, but I haven't done problems like this in a while. :( I think I may need some help.
I'm doing something wrong here.
@lochana Can you help me with this question?
He seems knowledgable about dilations.
I'm better with the basic matrix transformations.
I guess we'll just have to wait for @lochana because I want to make sure I'm not giving out incorrect answers. I just need to make sure I'm not giving out false answers.
That is the last thing I would want @stuck-help :(
thats fine i think im going to take a break for a little bit
Ok... once again, sorry...
it is a strange one:)
I know, right?
I found the center of dilation, but wasn't sure what to do from there... :P
I think you can tackle it only by considering length of each line
OH YEAH
WHY DIDNT I THINK OF THAT?!?
[\scale = \frac{length of AB after slcaled}{length of AB before scaled}\]
I was like taking the slopes of the lines and saying, ok so its 1/3 and -1/2 but you can just use pythagorean theorem to find the lengths of the lines and then divide.
\[scale = \frac{length of AB after slcaled}{length of AB before scaled}\]
yeah. you can do in that way too. but you have to be wet little bit:)
So, to find the lengths we can just use pythagorean theorem. \[AB = \sqrt{4^2+8^2}\] \[A'B' = \sqrt{3^2+6^2}\]
\[AB length(before) = \sqrt{45}\]\[AB length(after) = \sqrt{80}\]\[scale = \frac{\sqrt{80}}{\sqrt{45}} = \frac{4}{3}\]
exactly
Thank you so much for the clarification ^_^
I was struggling so much with this... :P
you are welcome:)
ah that's fine. it is a good thing:)
I was on the right track, but there was a much simpler route.
So, @stuck-help, there's your answer.
@malcolmmcswain |dw:1447444777875:dw| is this the start to it
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