Question

help me please!!!!!!!!!!!!!!!!!!!!! OMGGGGGGG!!!! X|

Answer 1

@Michele_Laino

Answer 2

@q12157

Answer 3

Have you learned the equation Q=mcT yet?

Answer 4

yes yes yes!!! !XD

Answer 5

Do you know what c is?

Answer 6

heat capacity

Answer 7

sorry...

Answer 8

i meant specific heat

Answer 9

so what is the specific heat capacity of water

Answer 10

the amount of energy it requires to raise the temperature of a 1Kg substance by 1 degreeeeeeeee

Answer 11

4.2X 10^3J/KgC

Answer 12

but pleaase answer my question please.........can't i just take 2 Kg of water and turn it into steam or something?!?1/1?!!?!?!?!??!!??!?!?

Answer 13

yesh but you need to know the temperature in which water turns into steam...which is?

Answer 14

hunnet

Answer 15

you can probably do the rest i believe

Answer 16

ive done the question for 2 KG and not 8Kg.....

Answer 17

i just took 2Kg water and turned it into stream...

Answer 18

Q = mct
Q = 8Kg X 4.2X10^3J/KGC X 100C-25C
Q = 2520J

Answer 19

i honestly don't know what to do :"(

Answer 20

ok thats the nergy required to boil 8Kg of water.... whats next?????

Answer 21

Find energy of the water at 25 degrees then find energy at of water at 100 degrees. You then subtract

Answer 22

yes but that would be for 8Kg of water right???????

Answer 23

any idea????

Answer 24

and since there is a change of state i think we need to add another formula.......Q = ml

Answer 25

4.46*10^6J?

Answer 26

what is that????????????/

Answer 27

i cant really think right now, but the answer is prolly something like this:
Q = mct
Q1=8kg*4.2*10^3*25--->Q2+Q3 where Q2=2*4.2*10^3*100 and Q3=2*2.23*10^6

so therefore energy added=Q2+Q3-Q1
which is equal to Q3 since Q2=Q1
and Q3=4.45*10^6

There is a good chance im wrong but im legit dying i need sleep

Answer 28

and by 4.45 i mean 4.46

Answer 29

ok but there is a change of state of matter....Q= ml......what about that, your turning water to stream

Answer 30

Q3 is the change of state

Answer 31

if im not mistaken m=2 l=2.23*10^6 J/kg or something

Answer 32

I dont remember

Answer 33

ok hun thanks....i love you,,,,, muuuuuuhhhaaaa, sweet dreams!! :")

Answer 34

yah night lol

Answer 35

sorry if im wrong tho xD

Answer 36

i'll figure it out eventually.... LOL

Answer 37

OK - first

you need to raise the temperature of the water from 25 C to 100C.

You were correct above and your calculation was:
Q = 8Kg X 4.2X10^3J/KGC X 100C-25C
Q = 2520J


BUT
now you need to add more energy to convert the water at 100 C to Steam at 100 C

for this you need the 'latent heat (or enthalpy) of vapourisation

and the equation is Q= mL

so there are 2 'lots' of energy required:
first 'specific heat' to raise the temp to 100
then 'latent heat' to turn the water into steam at 100 C

add them together for the answer

Answer 38

Thanks Mr Nood lol!
Turns out i slept 17 consecutive hours... wtf

Answer 39

imma give you a medal just for that....LOL

Answer 40

i figured out the question......you don't subtract, you divide by 4....since it's a 8:2 ratio.
i did it both ways, i'm getting the same answer!!!!!!! XD

Answer 41

and yes that's exactly what Mr.Noob said XD....

Answer 42

I have no idea why you seem fixated on 2kg

or any 8:2 ratio

use the specific heat capacity for 8kg raised 75 K
use the latent heat for 8kg from water at 100 C to steam at 100 C

add them together