Write a finite geometric series representing the total amount of water leaked after h hours. *I can't post a pic of the beaker but the fill line is at 75ml and the beaker goes 10,20,30,40,50,60,70,80,90,100*
so you you know any other information...?
The top of the page says, " Neil has a leaky faucet in his bathroom. He decides to find the amount of water leaking from the faucet over a period of time. For the first hour, he measured the volume of water that leaked by collecting it in a beaker."
ok... so what is the volume of water for the hour...?
The volume of water collected in the beaker in the first hour would be 75ml.
ok... so the leak is 75ml/h so what other information do you have..?
For the second hour the volume is 81.25 ml.
what about the 3rd hour...?
It doesn't tell me but it says the amount of water leaking from the faucet every hour increases uniformly by (1/12) of the amount leaked in the previous hour.
ok... so you have the initial term 75 common ratio 13/12 so does 81.15 = 75 x 13/12..?
Is that a geometric series though?
It will be |dw:1447451888182:dw| so the initial volume is 75 ml the common ratio is 13/12 so a turn in the series is \[T_{n} = 75 \times (\frac{13}{12})^{n - 1}\]
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