Question

Calculus help
http://prntscr.com/92ilwj

Answer 1

I dont know why i got d wrong

Answer 2

Solve\[7=2^3-9(2)^2+24(2)+d\]

Answer 3

f(2) = 7 = 1 * (2)^3 + (-9)*(2)^2 + 24*2 + d
f(4) = -9 = 1*(4)^3 + (-9)*(4)^2 + 24 *4 + d
f(3) = 5 = 1*(3)^3 + (-9)*(5)^2 + 24*3 + d
simplyfying we get..

f(2) = 7 = 8 + (-36) + 48 + d
--> f(2) = 7 = 20 + d
f(4) = -9 = 64 + (-144) + 96 + d
--> f(4) = -9 = 16 + d
f(3) = 5 = 27 + (-225) + 72 + d
--> f(3) = 5 = d - 126

adding them all up we get

3 = 3d -90
93 = 3d
d= 31

Answer 4

should be right if i didn't make any arithmetic mistakes..

Answer 5

i got it wrong :/

Answer 6

er

Answer 7

try d=-13

Answer 8

so you have a=1 and b=-9 and c=24
so let's plug those in:
\[f(x)=x^3-9x^2+24x+d \\ \text{ now using one of the points given we should be able \to find } d \\ \text{ say we use } (3,5) \\ f(3)=3^3-9(3)^2+24(3)+d \\ \text{ and remember } f(3)=5 \\ \text{ so solve the following for } d \\ 5=3^3-9(3)^2+24(3)+d\]

Answer 9

d=-13

Answer 10

that is right
5=27-81+72+d
5-27+81-72=d

Answer 11

@ospreytriple 's equation would have also worked he used the point (2,7)