Mathematics
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OpenStudy (pokiedokie):
simplify the expression using the imaginary unit i:
2√-24 + 6
simplify the expression:
(2-3i)/(1+5i)
please help and walk me through the steps!
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OpenStudy (lochana):
hint:\[i^2 = -1\]
OpenStudy (lochana):
\[2\sqrt{-1.24} + 6\]
OpenStudy (lochana):
still confused?
OpenStudy (pokiedokie):
do i distribute the 2 and then add 6 or is that not important?
OpenStudy (lochana):
no. you can put i^2 instead of -1\[2\sqrt{i^224} + 6\]
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OpenStudy (lochana):
get it?
OpenStudy (lochana):
i is the imaginary unit here.okay?
OpenStudy (pokiedokie):
yes
OpenStudy (lochana):
so we can say\[2\sqrt{i^2}\sqrt{24}+ 6\]
OpenStudy (lochana):
look at my previous one if you don't understand last one
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OpenStudy (lochana):
I think you still have problems.. right?
OpenStudy (pokiedokie):
im just taking a while to respond because i'm trying to understand it better
OpenStudy (lochana):
okay. that's fine. do you know why we use this i^2 thing here?
OpenStudy (pokiedokie):
no not really, sorry
OpenStudy (lochana):
because you can't solve \[\sqrt{-24}\]
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OpenStudy (lochana):
you can't square root negative numbers.
OpenStudy (pokiedokie):
ohhh, that makes sense, so what it's trying to do is make it positive then
OpenStudy (lochana):
yes. so we get rid of negative part using i^2.
we say \[i^2 = -1\]
OpenStudy (pokiedokie):
okay i see so it turns into positive 24 and then we square root it
OpenStudy (lochana):
\[\sqrt{-24} = \sqrt{-1.24} = \sqrt{i^224} = \sqrt{i^2}\sqrt{24}\]
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OpenStudy (lochana):
\[\sqrt{i^2}\sqrt{24} = i\sqrt{24}\]
OpenStudy (lochana):
okay?
OpenStudy (pokiedokie):
okay i think i understand it a little better
OpenStudy (lochana):
yes. now you can do further simplifying
\[i\sqrt{24} = i\sqrt{2^2.6}\]
OpenStudy (lochana):
that means \[2i\sqrt{6}\]
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OpenStudy (lochana):
so \[2\sqrt{-24} + 6 = 2i\sqrt{6} + 6\]
OpenStudy (lochana):
and \[2\sqrt{-24} + 6 = 2i\sqrt{6} + \sqrt{6}\sqrt{6}\]
OpenStudy (pokiedokie):
oh wow thank you so much, i was stuck on that question for an hour...
OpenStudy (lochana):
and I did a mistake:)
\[2\sqrt{-24} + 6 = \sqrt{6}(4i + \sqrt{6})\]
OpenStudy (lochana):
do it it again. you should get my last answer.
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OpenStudy (lochana):
what about 2nd one?
OpenStudy (pokiedokie):
i'm not exactly sure how to do it it's confusing me a lot
OpenStudy (lochana):
you want to get removed 'i' part from denominator.
OpenStudy (lochana):
denominator is (1 + 5i)
OpenStudy (pokiedokie):
okay, and i do that by adding to both sides?? or am i incorrect
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OpenStudy (lochana):
yes. you don't add things in fractions. you can't do that.
OpenStudy (lochana):
you need to multiply both sides by (1-5i)
OpenStudy (lochana):
\[\frac{(2-3i)(1-5i)}{(1+5i)(1-5i)}\]
OpenStudy (pokiedokie):
okay, and sorry that's what i meant i'm just a little stressed out
so its:
(2-3i)*(1+5i)
_____________
(1 + 5i) (1 + 5i)
OpenStudy (pokiedokie):
whoops
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OpenStudy (lochana):
it is not (1+5i). it should be (1-5i)
OpenStudy (pokiedokie):
oh okay! that makes a lot of sense
OpenStudy (lochana):
yeah. conjugate. you want to multiply by conjugate of (1+5i)
OpenStudy (lochana):
can you do it now?
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OpenStudy (pokiedokie):
yes, thank you so much
OpenStudy (lochana):
you are welcome:)