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Physics 17 Online
OpenStudy (anonymous):

An object was thrown vertically up and allowed to fall down. The acceleration of it will be -10m/s, when it is moving up and the acceleration will be 10m/s, when it is moving down. Why isn't the acceleration 0m/s at the highest point.

OpenStudy (irishboy123):

if [and clearly this is hypothetical and plain wrong] at the peak of flight, acceleration is actually zero, the the object will "freeze" at that point :-) it will be stuck there forever ie it's velocity is zero and acceleration is zero.... or until another force acts upon it....

OpenStudy (anonymous):

I didn't understand

OpenStudy (anonymous):

How can there be another force because weight is the only force in this instance

OpenStudy (irishboy123):

i didn't say there was another force !!! i was saying that in your analysis the object should freeze unless some force acted on it. if that is confusing, forget about it and think about the key question - why the object does not freeze. because you say that its velocity is zero and its acceleration is zero. so it must freeze....surely?!?! it is stuck at v = 0 forever..... and if you don't get this way of thinking, then just keeping mind that gravity doesnt get switched off. gravity is always switched on, and F = ma is always true. so object is always accelerating [or decelerating].

OpenStudy (anonymous):

I got it tks

OpenStudy (irishboy123):

cool 😀

OpenStudy (mrnood):

OK - you have also made a basic error in your first assertion: the acceleration is -10 m/s^2 AT ALL TIMES. It does NOT change from - to + when th edirection changes. It is the VELOCITY that changes direction, NOT the acceleration

OpenStudy (mrnood):

You have also got the units incorrect too: acceleration is in m/s^2 NOT m/s

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