Suppose that lengths of newborn girls are normally distributed with a mean of 49.2 cm and a standard deviation of 1.8 cm.Which lengths of female newborns are in the 90th percentile or higher?
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OpenStudy (daniellelovee):
@kropot72 please help me
OpenStudy (amistre64):
do you have a way to compute a normalCDF function?
OpenStudy (amistre64):
or is this just tables?
OpenStudy (daniellelovee):
no sorry just tables
OpenStudy (amistre64):
if we assume your tables are left tailed, then the upper 90 is equal to the lower 10
id start with defining your z score with that is given.
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OpenStudy (daniellelovee):
ok so μ = 49.2 and σ = 1.8
OpenStudy (amistre64):
\[z_{.0100}=\frac{x-mean}{sd}\]
the table gives you z_{.0100}and you are finding x right?
OpenStudy (amistre64):
you can use z_{.9000} as well if your left tail table goes that high
OpenStudy (daniellelovee):
alright sure
OpenStudy (amistre64):
49.2 + 1.8 |z|= x
how do you determine z?
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OpenStudy (daniellelovee):
would it be 0.90?
OpenStudy (amistre64):
prolly not ...find the closest field value on your table, to .0100 or .9000 and then add the row to the col.
|dw:1447521717501:dw|