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Mathematics 6 Online
OpenStudy (daniellelovee):

Suppose that lengths of newborn girls are normally distributed with a mean of 49.2 cm and a standard deviation of 1.8 cm.Which lengths of female newborns are in the 90th percentile or higher?

OpenStudy (daniellelovee):

@kropot72 please help me

OpenStudy (amistre64):

do you have a way to compute a normalCDF function?

OpenStudy (amistre64):

or is this just tables?

OpenStudy (daniellelovee):

no sorry just tables

OpenStudy (amistre64):

if we assume your tables are left tailed, then the upper 90 is equal to the lower 10 id start with defining your z score with that is given.

OpenStudy (daniellelovee):

ok so μ = 49.2 and σ = 1.8

OpenStudy (amistre64):

\[z_{.0100}=\frac{x-mean}{sd}\] the table gives you z_{.0100}and you are finding x right?

OpenStudy (amistre64):

you can use z_{.9000} as well if your left tail table goes that high

OpenStudy (daniellelovee):

alright sure

OpenStudy (amistre64):

49.2 + 1.8 |z|= x how do you determine z?

OpenStudy (daniellelovee):

would it be 0.90?

OpenStudy (amistre64):

prolly not ...find the closest field value on your table, to .0100 or .9000 and then add the row to the col. |dw:1447521717501:dw|

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