Question

How to factor by grouping: 2ax^2 + 6a - x^2 - 3

Answer 1

what is the GCF of the first 2 terms?

Answer 2

2ax^2 and 6a ?

Answer 3

2a

Answer 4

Do i need to do 2ax(x+3) or 2a(x^2+3)

Answer 5

ok so taking that out we get
2a(x^2 + 3)

now we need to factor the 3rd and 4th terms and try to get x^2 + 3 in the parentheses

Answer 6

your first try is wrong If you expand it you get 2ax^2 + 6ax which is different from the original

Answer 7

2a(x^2+3) - x(x+3)

Answer 8

?....

Answer 9

no
-x(x - 3) gives -x^@ + 3x and you need -x^2 - 3

Answer 10

you need to take out -1 for the last 2 terms

Answer 11

-1 is the GCF of -x^2 and - 3

Answer 12

so we have
2a(x^2+3) - 1(x^2+3)

Answer 13

So -1 (x^2+)

Answer 14

Ohh

Answer 15

if you expand the second part you see it comes out to -x^2 - 3 which is what we eant

Answer 16

And then (x^2+3)*(2a-1)?

Answer 17

yes

Answer 18

Though you don't need the *

Answer 19

Thank u so much! I knew how to do easier ones but i wasnt sure about this one:) yes yes, i dont write on the paper xd

Answer 20

yw