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OpenStudy (anonymous):
WILL MEDAL!!
Please help!
Find the real or imaginary solutions of each equation using factoring.
x^3 + 2x^2+5x+10=0
x^4-10x^2=-9
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OpenStudy (irishboy123):
i fancy this one, for sure
\[x^4-10x^2=-9\]
think: \(z = x^2\)
OpenStudy (xapproachesinfinity):
the first one notice that you can recollect (group) and factor
OpenStudy (xapproachesinfinity):
and the second is as @IrishBoy123 mentioned think of x^2 as another variable z
OpenStudy (xapproachesinfinity):
so in other words you will just get a quadratic equation which is nicer to deal with
OpenStudy (anonymous):
so you're saying do z^2 + 10z
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OpenStudy (anonymous):
@xapproachesinfinity ^^
OpenStudy (xapproachesinfinity):
close but not quite
\[z^2-10z=-9 \Longrightarrow z^2-10z+9=0 \]
OpenStudy (anonymous):
Ok thank you! Do you know how to do the first one?
OpenStudy (xapproachesinfinity):
so now you are trying to solve \[z^2-10z+9=0\] for z
once you found z return back to x
OpenStudy (xapproachesinfinity):
the first is really straight forward
\[x^3 + 2x^2+5x+10=0 \Longrightarrow (x^3+2x^2)+(5x+10)=0\]
\[x^2(x+2)+5(x+2)=0 \Longrightarrow (x^2+5)(x+2)=0 \]
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OpenStudy (anonymous):
Thank you! :)
OpenStudy (xapproachesinfinity):
welcome
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