I have a question about integrals and solving! I will post the problem below.
@nincompoop
@abb0t
well you can factor out the 7
as it will become
\[\int\limits_{3}^{5} 7(f(x) + 1)dx = 7\int\limits_{3}^{5} (f(x) + 1) dx\]
I figured out that much. I guess I'm just mainly confused on how to solve after that.
@campbell_st
Here are some ways you can break down the left side,\[\large\rm \color{royalblue}{\int\limits_3^5 7f(x)+7~dx}=7\]\[\large\rm \color{royalblue}{\int\limits_3^5 7f(x)dx+\int\limits_3^5 7~dx}=7\]\[\large\rm \color{royalblue}{7\int\limits_3^5 f(x)dx+\int\limits_3^5 7~dx}=7\]
Do you understand how that helps us?
I think so
@zepdrix
You think so? lol :)
I understand how you got those equations, but not sure how to apply them further
Well we're trying to solve for this orange part,\[\large\rm 7\color{orangered}{\int\limits\limits_3^5 f(x)dx}+\int\limits\limits_3^5 7~dx=7\]Just think of this as your "variable" if that helps,\[\large\rm 7\color{orangered}{y}+\int\limits\limits_3^5 7~dx=7\]Solve for y. That's what the question is asking you to do.
so y = -1 ?
Ah yes, good job! :)
Thank you!
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