Question

Write an equation of the line passing through the point (5, 1) that is perpendicular to the line 5x+3y=15. (y=mxtb format)

Answer 1

Perpendicular to a line means the negative reciprocal of the slope. So first, let's find the slope of x+7y=8. To do that, we need to rearrange it to slope intercept form (y=mx+b).

Answer 2

If you have a know that 5x+3y=15 ─> y=(-5/3)x+5,
then it's slope has to be \(-1/\color{red}{(-5/3)}\)

Answer 3

Negative reciprocal of −17 is 7. So the perpendicular line has a slope of 7. And, we can begin to create the equation for the perpendicular line: y=7x+b.

Using the information in the original problem, we can find the value of the y-intercept, b. The line must pass through (-4, 42). Simply plug those values into y=7x+b and solve for b.

−42=7(−4)+b
−42=−28+b
−42+28=b
−14=b

Answer 4

so y=7x-14

Answer 5

Negative reciprocal of −17 is 7. So the perpendicular line has a slope of 7. And, we can begin to create the equation for the perpendicular line: y=7x+b.

Using the information in the original problem, we can find the value of the y-intercept, b. The line must pass through (-4, 42). Simply plug those values into y=7x+b and solve for b.

−42=7(−4)+b
−42=−28+b
−42+28=b
−14=b

Answer 6

stop spamming

Answer 7

and negative reciprocal of -17 is 1/17

Answer 8

@Compassionate

mods see deleted comments

have fun in being rude!

Answer 9

@SolomonZelman also do know 5x+2y=12. in slope intercept form?

Answer 10

i just wanna know how to make 5x+2y=12. in slope intercept form jc

Answer 11

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and this site manger the police

Answer 12

u willy wonka

Answer 13

Please stop spaming

Answer 14

Refer to the attachment created with the Mathematica program.

Answer 15

@robtobey ty