Find an equation for the nth term of the arithmetic sequence. -20, -16, -12, -8, ...
an arithmetic equation is defined by the starting value and the common difference. do you know what these are?
sorry, an arithmetic "sequence", not equation
you add four so +4 is the common difference?
d = a_{n+1} - a_{n} = -16 - (-20) = 4 a_{0} = first of sequence = -20 a_{n} = a_{0} + d(n-1) d_{n} = -20 + 4(n-1)
correct!
and would starting value just be -20
excellent
can you help me with another
so, if you start with -20 and add 4 at each step (except the 0th step) you get this \(a_n=a_0 +d \cdot \left(n-1\right)\) where n can be any whole number
Find the first six terms of the sequence. \[a _{1}=4\] [a _{n} = a _{n-1}+7\] how do i do this
oops, n can be any natural number (that is 1, 2, 3, ...)
just plug in ... so if you want to find \(a_2\) just take \(a_1\) and add 7
good luck!
thank u
you're welcome
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