how do you factor this expression will give medal and fan help
\[a ^{4}+7a ^{2}+6\]
@Jack_Prism
Im pretty sure this equation is already factored
thats what they gave me and told me to factor that was the whole question
See but there is nothing more you can do to the problem
so what do i say to anwser
answer*
You just re-write the equation
ok
yup
thanks
you are very welcome
tarzinian
Tris, this problem is not `already factored`. It is the opposite, it is fully expanded. Do you still need assistance with this one?
yes
Zep, Is that true....i thought i was already factored out?
Factoring is to break it down into groups of multiplication :) You're probably mixing words up and thinking of "expanding out"
If you had this problem: \(\large\rm x^2+7x+6\) Would you know how to factor it Tris? :)
@Mehek14 Someone needs your help! To the Mehek-mobile!
Seriously tho this place is filled to the brim with mathletes
I apologize for my mistake, thank you zep
i had a feeling they wouldnt give the question if i cant give an answer other than the question but it says factor the polynomial completely
What's with all these equations and theorems? Is it that hard to give a simple answer?
You've clearly missed the point of this site CheesecakePuppy <.< You are no kitten at all...
Tris, did you not see my last question? Are you able to factor this? \(\large\rm x^2+7x+6\)
@zepdrix
sorry my computer is broken i am using my moms this guy came in to take it and fix it
Haha weird XD
yes\[\left( x +1\right)\left( x+6 \right)\]
Ok good. Notice that your problem is actually this:\[\large\rm a^4+7a^2+6\quad=\color{orangered}{(a^2)}^2+7\color{orangered}{(a^2)}+6\]Making the substitution \(\large\rm \color{orangered}{(a^2)=x}\) gives us:\[\large\rm \color{orangered}{(a^2)}^2+7\color{orangered}{(a^2)}+6\quad= \color{orangered}{x}^2+7\color{orangered}{x}+6\]
where did you get x from
I was making a substitution to simplify the 4th degree polynomial into a quadratic.
oh yeah
It's a weird little trick that you have to get used to.
But do you see what we're going to end up with? \[\large\rm (\color{orangered}{x}+1)(\color{orangered}{x}+6)\quad=(\color{orangered}{?}+1)(\color{orangered}{?}+6)\]Undo the substitution as a final step.
\[\left( a ^{2}+1 \right)\left( a ^{2}+6 \right)\]
Yay good job \c:/
thx
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