Question

Find the following limit

Answer 1

\[\lim_{x \rightarrow 0+}\frac{ x^{2} - 4x}{ 1-e^{2x} }\]

Answer 2

We have to use l'hopital rule

Answer 3

so first get the derivative of the numerator and denominator. \[=\frac{ 2x-4 }{ -2e ^{2x} }\] and then plug in zero into x

Answer 4

Btw we have to use l'hospital rule because limit as x->0 for the numerator is 0 and same with the denominator \[\lim_{x \rightarrow 0} = \frac{ 0 }{ 0 }\]

Answer 5

thank you I understand it better now!