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Mathematics 15 Online
OpenStudy (matlee):

Need help with precalculus!

TheSmartOne (thesmartone):

Hi! What is your question? :)

OpenStudy (matlee):

OpenStudy (matlee):

Hllo , i dont know anything

TheSmartOne (thesmartone):

You must know something. :)

OpenStudy (anonymous):

which one? amplitude?

TheSmartOne (thesmartone):

Ok, so normally, what is the period of the trig function tan

OpenStudy (matlee):

Nothing :(

OpenStudy (matlee):

I need help wit all of them

TheSmartOne (thesmartone):

Ok, we'll do them all :)

OpenStudy (matlee):

Thank you!

OpenStudy (matlee):

Will you be abe to receive my owl bucks?

TheSmartOne (thesmartone):

Depends, I'm not a QH, but you could send it from the profile :P

TheSmartOne (thesmartone):

But, back to the worksheet. :)

TheSmartOne (thesmartone):

y = A sin(Bx + C) + D amplitude is A period is 2π/B phase shift is −C/B vertical shift is D

OpenStudy (matlee):

Tis is for number 1?

TheSmartOne (thesmartone):

Yes :)

OpenStudy (matlee):

Ok,

TheSmartOne (thesmartone):

We are given: \(\sf\Large y = -4tan(\frac{1}{2}x)\) The amplitude is |-4| = ?

OpenStudy (matlee):

4

OpenStudy (alexandervonhumboldt2):

correct

TheSmartOne (thesmartone):

correct :)

OpenStudy (matlee):

So amps will ablways be absolute value? also my thing keeps glitcching have to refresh to type again sorry

OpenStudy (alexandervonhumboldt2):

yes

OpenStudy (matlee):

Ok thank you

TheSmartOne (thesmartone):

ok, now normally the period for tan is pi

TheSmartOne (thesmartone):

got to refresh too >.<

OpenStudy (matlee):

Lol

OpenStudy (matlee):

Thats fine

TheSmartOne (thesmartone):

\(\sf\Large y = -4tan(\frac{1}{2}x)\) So period will be \(\sf\Large \frac{\pi}{\frac{1}{2}} = ?\)

OpenStudy (matlee):

@pooja195 thats k ppooja it was my faut i just noticed i int press ask a qualified helper lol

TheSmartOne (thesmartone):

it's ok, pooja is offline :)

TheSmartOne (thesmartone):

and I'm better at trig :P

OpenStudy (matlee):

O lol, Period will always be 2pi/b? I have t mae sure cus i have a test tommorow

OpenStudy (matlee):

haha

TheSmartOne (thesmartone):

2pi/b is only for cos and sin

TheSmartOne (thesmartone):

pi/b is for tan

OpenStudy (matlee):

o ok

OpenStudy (matlee):

so pi/1/2 = uhm

OpenStudy (matlee):

1.57

TheSmartOne (thesmartone):

pi / 1/2 = pi * 2/1 = ?

OpenStudy (matlee):

Oh is that how you do it! I got 6.3 or 6.28

TheSmartOne (thesmartone):

just leave it as 2pi :)

OpenStudy (matlee):

Ok lol thats much better

TheSmartOne (thesmartone):

ok, now we need to graph it

TheSmartOne (thesmartone):

we need to graph another equation actually :P

OpenStudy (matlee):

Wow theres alot of people looking in here

OpenStudy (matlee):

Ok

OpenStudy (matlee):

Do you still have to refresh?

OpenStudy (alexandervonhumboldt2):

lots of people because this is a qh question

TheSmartOne (thesmartone):

yea, going to refresh again >.<

OpenStudy (matlee):

Oo, i think its lagging lol i see 5 pople on the top and 7 people on the bottom

TheSmartOne (thesmartone):

now it's finally fixed! ;)

OpenStudy (matlee):

Ok great its working for mine too

TheSmartOne (thesmartone):

it keeps bringing @spraguer to view this post and that's causing the lag

OpenStudy (matlee):

Hhaah, really?

TheSmartOne (thesmartone):

yea, ok lets graph it

TheSmartOne (thesmartone):

https://www.desmos.com/calculator/v1ttwtxx3j

TheSmartOne (thesmartone):

you just need to graph this much http://prntscr.com/938xhg

OpenStudy (matlee):

Wait how would i know to graph that?

OpenStudy (matlee):

LOl im so sorry i didnt see that part.

TheSmartOne (thesmartone):

because you should know how to graph y = sin(x) and for each point in sin(x), you just miltiply the y value by -3

TheSmartOne (thesmartone):

added y = sin(x) so you can see the difference :) https://www.desmos.com/calculator/qyjpaojno8

TheSmartOne (thesmartone):

see http://prntscr.com/938yl0

OpenStudy (matlee):

So i would draw whats on the print screen into the graph?

TheSmartOne (thesmartone):

yes, from this one http://prntscr.com/938xhg for question #2 :)

TheSmartOne (thesmartone):

also, remember to write those points on it :P

OpenStudy (matlee):

Im sorry for not bieng so knowledagle in those things. But how did u get that

OpenStudy (matlee):

Are those formula based like they are always there for this type of equation or o i nee to input something int othe calculator?

TheSmartOne (thesmartone):

Also, the graphs of y = sin(x) should be memorized :)

OpenStudy (matlee):

Ok thank you, are there ones for cos and tan?

TheSmartOne (thesmartone):

anyways, you need to memorize a few points of the graph of y = sin(x) so that way you can connect the points to make the graph and the graph is never ending so you will only have to do it for 1 period :)

OpenStudy (matlee):

lol

TheSmartOne (thesmartone):

the graphs for cos(x) and tan(x) are different cos(x) is kind of similar, but tan(x) is way different :P

OpenStudy (matlee):

Ok i will check them later thanks

OpenStudy (wintersuntime):

Cough Cough Mathlete xD

OpenStudy (matlee):

So on number 2 i would graph the first period?

TheSmartOne (thesmartone):

yes, you graph this: http://prntscr.com/938xhg

OpenStudy (matlee):

Ok thank you

OpenStudy (matlee):

Does number 1 have to do with number 2?

OpenStudy (wintersuntime):

wow

TheSmartOne (thesmartone):

nope

OpenStudy (wintersuntime):

lol can't stop laughing

TheSmartOne (thesmartone):

#1 and #2 are seperate :)

TheSmartOne (thesmartone):

ok, so now #3, right? :)

OpenStudy (matlee):

=-3sinx is nothing i just write y=sin(x)?

OpenStudy (matlee):

Lol how od i give u owl bucks dii give them alredy?

TheSmartOne (thesmartone):

You can't rate me since I'm not a QH :P

OpenStudy (matlee):

o :(

TheSmartOne (thesmartone):

so since you can't rate me, I can't give owlbucks :P

TheSmartOne (thesmartone):

get*

TheSmartOne (thesmartone):

now for #3 ok for #3 sec(x) = 1/cos(x) cos(x) has a period of 2pi, so sec(x) has a period of

OpenStudy (matlee):

Ok well so far i apprciate your help

TheSmartOne (thesmartone):

sec(x) also will have a period of 2pi :)

TheSmartOne (thesmartone):

and since 1/2 sec (x) has no 'b' the period is just still 2pi :)

OpenStudy (matlee):

Ok thank you so the answer would be 2pi?

TheSmartOne (thesmartone):

yup :)

TheSmartOne (thesmartone):

graph for it https://www.desmos.com/calculator/hbrofsnou8

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