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Locate the foci of the ellipse. Show your work. x^2/36+y^2/11=1
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@celinegirl
if you asked my to guess i would say 6 and squareroot of 11 loll
no one likes these conic section questions, but they are not that hard
the center is evidently \((0,0)\) the only thing we need to get is the way it is oriented
|dw:1447640289909:dw|
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left?
yes
because the larger number is under the \(x^2\) terms
now all we need to know is how many units to the left and right of \((0,0)\) the foci are
it is \[\sqrt{a^2-b^2}\] which in your case is easy since \(a^2=36,b^2=11\) so it is \[\sqrt{36-11}=\sqrt{25}\]
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aka 5
what is 5 units to the left of \((0,0)\)?
(5,0)and(−5,0)
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