Question

3x+2y=6
5x+3y=15
~solve using Graphing
~Solve using Substitution
~Solve using Elimination
~Write an application problem

Answer 1

which part is hardest for you?

Answer 2

graphing & elimination ( i don't know how to get a negative number instead of a postive with the numbers given) ~nothing times 3 gives -5~

Answer 3

okay. to graph equations, first you need to write equations for y

\(y = \frac{6-3x}{2}\) is first one.

Answer 4

can you tell me second one? like I did for first one

Answer 5

\(y= \frac{15-5x}{3}\) yea?

Answer 6

\[y=\frac{ 15-5 }{ 3 }\] .??

Answer 7

5x. not just 5

Answer 8

why does it have to subbtract.?

Answer 9

subtract*

Answer 10

\[3x +2y = 6 \\ 3x + 2y - 3x = 6 -3x \\ 2y = 6 -3x \\ \frac{2y}{2} = \frac{6-3x}{2} \\ y = \frac{6-3x}{2}\]

Answer 11

do same with 2nd one. you will get my answer

Answer 12

to be honest i have no clue what you just did.. our teacher showed us an "easy" method..
which was... what times 3 gives us 6.. well 2, 3x2=6, so 2 was our x.. now what times 2 gives us 6.. well 3, 2x3=6, so 3 was our y..

Answer 13

so our points were (2,3) & she graphed..

Answer 14

well, at the end, you have to graph them anyways. so these are the graphs

Answer 15

so, solutions are points where 2 graphs meet. that's (0,3)

Answer 16

well thanks for your help and time I appreciate it.. :)

Answer 17

you are welcome:)

Answer 18

c