Question

Probably a easy question...

Answer 1

How do I make this expression:
\[e ^{\frac{ x }{ x+1 }}\]

look like this:
\[e ^{1-\frac{ 1 }{ x+1 }}\]

algebraically

Answer 2

@ganeshie8 solve this for me!

Answer 3

have you tried long division ?

Answer 4

you could also rearrange the numberator like this :

\[\dfrac{x}{x+1} = \dfrac{(x+1)-1}{x+1} \]

Answer 5

@ganeshie8 so what is it actually we are doing? is it just add and subtract 1?

Answer 6

Exactly !

Answer 7

next, split up the fractions

Answer 8

\[\dfrac{x}{x+1} = \dfrac{(x+1)-1}{x+1} = \dfrac{x+1}{x+1} - \dfrac{1}{x+1} \]

Answer 9

thanks @ganeshie8

Answer 10

yw!